I’m trying to create a code that will solve for x using the quadratic formula. For the outputs I don’t want it to display the imaginary numbers…only real numbers. I set the value inside the square root to equal the variable called «root» to determine if this value would be pos/neg (if it’s neg, then the solution would be imaginary).
This is the code.
import math
print("Solve for x when ax^2 + bx + c = 0")
a = float(input("Enter a numerical value for a: "))
b = float(input("Enter a numerical value for b: "))
c = float(input("Enter a numerical value for c: "))
root = math.pow(b,2) - 4*a*c
root2 = ((-1*b) - math.sqrt(root)) / (2*a)
root1 = ((-1*b) + math.sqrt(root)) / (2*a)
for y in root1:
if root>=0:
print("x =", y)
elif root<0:
print('x is an imaginary number')
for z in root2:
if root>=0:
print("or x =", z)
elif root<0:
print('x is an imaginary number')
This is the error code:
File "/Users/e/Documents/Intro Python 2020/Project 1/Project 1 - P2.py", line 25, in <module>
for y in root1:
TypeError: 'float' object is not iterable
The error occurs at the line:
for y in root1:
How do I fix this error?
asked Apr 10, 2020 at 23:39
4
I understand you are using the quadratic equation here. An iterable is something like a list. A variable with more than 1 element. In your example
root1 is a single float value. root2 is also a single float value. For your purposes, you do not need either lines with the «for». Try removing the for y and for z lines and running your code.
To help you understand, a float value is simply a number that has decimals.
answered Apr 10, 2020 at 23:42
SriSri
2,2312 gold badges16 silver badges22 bronze badges
Well, the error is pretty self explanatory: you are trying to loop over root1 and root2 which are floats, not lists.
What I believe you wanted to do instead is simply use if/else blocks:
if root >= 0:
print("x =", root1)
print("x =", root2)
else:
print("x is an imaginary number")
answered Apr 10, 2020 at 23:45
Anis R.Anis R.
6,5282 gold badges13 silver badges37 bronze badges
I’m trying to create a code that will solve for x using the quadratic formula. For the outputs I don’t want it to display the imaginary numbers…only real numbers. I set the value inside the square root to equal the variable called «root» to determine if this value would be pos/neg (if it’s neg, then the solution would be imaginary).
This is the code.
import math
print("Solve for x when ax^2 + bx + c = 0")
a = float(input("Enter a numerical value for a: "))
b = float(input("Enter a numerical value for b: "))
c = float(input("Enter a numerical value for c: "))
root = math.pow(b,2) - 4*a*c
root2 = ((-1*b) - math.sqrt(root)) / (2*a)
root1 = ((-1*b) + math.sqrt(root)) / (2*a)
for y in root1:
if root>=0:
print("x =", y)
elif root<0:
print('x is an imaginary number')
for z in root2:
if root>=0:
print("or x =", z)
elif root<0:
print('x is an imaginary number')
This is the error code:
File "/Users/e/Documents/Intro Python 2020/Project 1/Project 1 - P2.py", line 25, in <module>
for y in root1:
TypeError: 'float' object is not iterable
The error occurs at the line:
for y in root1:
How do I fix this error?
asked Apr 10, 2020 at 23:39
4
I understand you are using the quadratic equation here. An iterable is something like a list. A variable with more than 1 element. In your example
root1 is a single float value. root2 is also a single float value. For your purposes, you do not need either lines with the «for». Try removing the for y and for z lines and running your code.
To help you understand, a float value is simply a number that has decimals.
answered Apr 10, 2020 at 23:42
SriSri
2,2312 gold badges16 silver badges22 bronze badges
Well, the error is pretty self explanatory: you are trying to loop over root1 and root2 which are floats, not lists.
What I believe you wanted to do instead is simply use if/else blocks:
if root >= 0:
print("x =", root1)
print("x =", root2)
else:
print("x is an imaginary number")
answered Apr 10, 2020 at 23:45
Anis R.Anis R.
6,5282 gold badges13 silver badges37 bronze badges
Python can only iterate over an iterable object. This is a type of object that can return its members one at a time. If you try to iterate over a non-iterable object, like a floating-point number, you see an error that says “TypeError: ‘float’ object not iterable”.
In this guide, we talk about what this error means and why you may encounter it. We walk through an example to help you understand how to resolve this error in your code.
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TypeError: ‘float’ object not iterable
Iterable objects include list, strings, tuples, and dictionaries. When you run a for loop on these data types, each value in the object is returned one by one.
Numbers, such as integers and floating points, are not iterable. There are no members in an integer or a floating-point that can be returned in a loop.
The result of the “TypeError: ‘float’ object not iterable” error is usually trying to use a number to tell a for loop how many times to execute instead of using a range() statement.
An Example Scenario
Here, we write a program that calculates the factors of a number. To start, we ask the user to insert a number whose factors they want to calculate:
factor = float(input("Enter a number: "))
The input() method returns a string. We cannot perform mathematical operations on a string. We’ve used the float() method to convert the value returned by input() to a floating-point number so that we can use it in a math operation.
Next, we write a for loop that calculates the factors of our number:
for n in factor:
if factor % n == 0:
print("{} is a factor of {}.".format(factor, n))
This loop should go through every number until it reaches “factor”.
This loop uses the modulo operator to check whether there is a remainder left after dividing the factor by “n”, which is the number in an iteration of our loop. If there is a remainder, “n” is not a factor. If there is a remainder, our “if” statement executes and prints a message to the console.
Run our code and see what happens:
Enter a number: 8 Traceback (most recent call last): File "main.py", line 3, in <module> for n in factor: TypeError: 'float' object is not iterable
Our code returns a TypeError.
The Solution
In our example above, we’ve tried to iterate over “factor”, which is a float. We cannot iterate over a floating-point number in a for loop. Instead, we should iterate over a range of numbers between 1 and the number whose factor we want to calculate.
To fix our code, we need to use a range() statement. The range() statement generates a list of numbers in a specified range upon which a for loop can iterate. Let’s revise our for loop to use a range() statement:
for n in range(1, int(factor) + 1):
if factor % n == 0:
print("{} is a factor of {}.".format(factor, n))
Our range() statement generates a list of numbers between one and the value of “factor” plus one.
We have added 1 to the upper end of our range so that our “factor” number is considered a factor. Our for loop can then iterate over this list. We’ve converted “factor” to an integer in our code because the range() statement does not accept floating point numbers.
Run our code again and see what happens:
8.0 is a factor of 1. 8.0 is a factor of 2. 8.0 is a factor of 4. 8.0 is a factor of 8.
Our code successfully returns a list of all the factors of the number we inserted into our program.
Conclusion
The Python “TypeError: ‘float’ object not iterable” error is caused when you try to iterate over a floating point number as if it were an iterable object, like a list or a dictionary.
To solve this error, use a range() statement if you want to iterate over a number. A range statement generates a list of numbers in a given range upon which a for loop can iterate.
Now you’re ready to fix this common Python error in your code!
In this article, we will learn about the error “TypeError: ‘float’ object is not iterable”. This error occurs when we try to iterate through a float value which we know is not iterable.
Let us understand it more with the help of an example.
Example 1:
for i in 3.4:
print("this doesn't work")Output:
File "none3.py", line 1, in <module>
for i in 3.4:
TypeError: 'float' object is not iterableExplanation:
In the above example, we are trying to iterate through a ‘for loop’ using a float value. But the float is not iterable. Float objects are not iterable because of the absence of the __iter__ method. Which we have discussed about in the below example 2.
Thus the error “TypeError: float object is not iterable” occurs.
Example 2:
list = [2,4,8,3]
for x in list:
print(x)Output:
2
4
8
3Explanation:
In the above example, we are trying to print the list elements using the ‘for loop’. since the list is iterable, thus we can use the for loop for iteration.
To know whether an object is iterable or not we can use the dir() method to check for the magic method __iter__. If this magic method is present in the properties of specified objects then that item is said to be iterable
To check, do: dir(list) or dir(3.4)
Code:
List= [ ]
print(dir(list))Output:
['__add__', '__class__', '__contains__', '__delattr__', '__delitem__', '__dir__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__getitem__', '__gt__', '__hash__', '__iadd__', '__imul__', '__init__', '__init_subclass__', '__iter__', '__le__', '__len__', '__lt__', '__mul__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__reversed__', '__rmul__', '__setattr__', '__setitem__', '__sizeof__', '__str__', '__subclasshook__', 'append', 'clear', 'copy', 'count', 'extend', 'index', 'insert', 'pop', 'remove', 'reverse', 'sort']__iter__magicmethod is present.
Code:
print(dir(3.4))Output:
['__abs__', '__add__', '__bool__', '__class__', '__delattr__', '__dir__', '__divmod__', '__doc__', '__eq__', '__float__', '__floordiv__', '__format__', '__ge__', '__getattribute__', '__getformat__', '__getnewargs__', '__gt__', '__hash__', '__init__', '__init_subclass__', '__int__', '__le__', '__lt__', '__mod__', '__mul__', '__ne__', '__neg__', '__new__', '__pos__', '__pow__', '__radd__', '__rdivmod__', '__reduce__', '__reduce_ex__', '__repr__', '__rfloordiv__', '__rmod__', '__rmul__', '__round__', '__rpow__', '__rsub__', '__rtruediv__', '__set_format__', '__setattr__', '__sizeof__', '__str__', '__sub__', '__subclasshook__', '__truediv__', '__trunc__', 'as_integer_ratio', 'conjugate', 'fromhex', 'hex', 'imag', 'is_integer', 'real']__iter__ magic method is absent.
Conclusion
The presence of the magic method __iter__ is what makes an object iterable. From the above article, we can conclude that the __iter__ method is absent in the float object. Whereas it is present in the list object. Thus float is not an iterable object and a list is an iterable object.