Vba excel ошибка next without for

This error occurs when the condition is not closed.
You must don’t forger close if conditions.

for example:

Public Sub start_r()

    LastRow = SPT_DB.Range("D" & Rows.count).End(xlUp).Row

Dim i As Long
For i = 3 To 132

    State = Cells(1, i)

    Dim j As Long
    For j = 2 To LastRow

        m = SPT_DB.Cells(j, 4).Value
        z = SPT_DB.Cells(j, 5).Value
        n1 = SPT_DB.Cells(j, 6).Value
        fc = SPT_DB.Cells(j, 7).Value
        am = SPT_DB.Cells(j, 8).Value
        sp = SPT_DB.Cells(j, 10).Value
        sr = SPT_DB.Cells(j, 11).Value
        liq = SPT_DB.Cells(j, 13).Value

        num1 = Val(Left(State, 1))
        num2 = Val(Mid(State, 3, 1))
        num3 = Val(Mid(State, 5, 1))
        num4 = Val(Mid(State, 7, 1))
        num5 = Val(Mid(State, 9, 1))

        Dim spt_class As spt_class
        Set spt_class = New spt_class

        Select Case num1
            Case Is = 1: Call spt_class.rd_r1
            Case Is = 2: Call spt_class.rd_r2
            Case Is = 3: Call spt_class.rd_r3
            Case Is = 4: Call spt_class.rd_r4
        End Select

        Select Case num2
            Case Is = 1: Call spt_class.msf_r1
            Case Is = 2: Call spt_class.msf_r2
            Case Is = 3: Call spt_class.msf_r3
            Case Is = 4: Call spt_class.msf_r4
            Case Is = 5: Call spt_class.msf_r5
            Case Is = 6: Call spt_class.msf_r6
        End Select

        Select Case num3
            Case Is = 0:
            Case Is = 1: Call spt_class.n1_cs_r1
            Case Is = 2: Call spt_class.n1_cs_r2
            Case Is = 3: Call spt_class.n1_cs_r3
        End Select

        Select Case num4
            Case Is = 0:
            Case Is = 1: Call spt_class.dr_r1
            Case Is = 2: Call spt_class.dr_r2
            Case Is = 3: Call spt_class.dr_r3
            Case Is = 4: Call spt_class.dr_r4
        End Select

        Select Case num5
            Case Is = 1: Call spt_class.crr_r1
            Case Is = 2: Call spt_class.crr_r2
            Case Is = 3: Call spt_class.crr_r3
            Case Is = 4: Call spt_class.crr_r4
            Case Is = 5: Call spt_class.crr_r5
            Case Is = 6: Call spt_class.crr_r6
            Case Is = 7: Call spt_class.crr_r7
            Case Is = 8: Call spt_class.crr_r8
            Case Is = 9: Call spt_class.crr_r9
        End Select

        Call spt_class.lvr_r

    Next j


        If cnt_f_1_all = 0 Then
            Cells(4, i) = 0
        Else
            Cells(4, i) = cnt_f_1_liq * 100 / cnt_f_1_all
            Cells(4, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_2_all = 0 Then
            Cells(5, i) = 0
        Else
            Cells(5, i) = cnt_f_2_liq * 100 / cnt_f_2_all
            Cells(5, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_3_all = 0 Then
            Cells(6, i) = 0
        Else
            Cells(6, i) = cnt_f_3_liq * 100 / cnt_f_3_all
            Cells(6, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_4_all = 0 Then
            Cells(7, i) = 0
        Else
            Cells(7, i) = cnt_f_4_liq * 100 / cnt_f_4_all
            Cells(7, i).NumberFormat = "#,##0.00"
        End If


        If cnt_f_n0_1_all = 0 Then
            Cells(14, i) = 0
        Else
            Cells(14, i) = cnt_f_n0_1_liq * 100 / cnt_f_n0_1_all
            Cells(14, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n0_2_all = 0 Then
            Cells(15, i) = 0
        Else
            Cells(15, i) = cnt_f_n0_2_liq * 100 / cnt_f_n0_2_all
            Cells(15, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n0_3_all = 0 Then
            Cells(16, i) = 0
        Else
            Cells(16, i) = cnt_f_n0_3_liq * 100 / cnt_f_n0_3_all
            Cells(16, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n0_4_all = 0 Then
            Cells(17, i) = 0
        Else
            Cells(17, i) = cnt_f_n0_4_liq * 100 / cnt_f_n0_4_all
            Cells(17, i).NumberFormat = "#,##0.00"
        End If


        If cnt_f_n1_1_all = 0 Then
            Cells(24, i) = 0
        Else
            Cells(24, i) = cnt_f_n1_1_liq * 100 / cnt_f_n1_1_all
            Cells(24, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n1_2_all = 0 Then
            Cells(25, i) = 0
        Else
            Cells(25, i) = cnt_f_n1_2_liq * 100 / cnt_f_n1_2_all
            Cells(25, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n1_3_all = 0 Then
            Cells(26, i) = 0
        Else
            Cells(26, i) = cnt_f_n1_3_liq * 100 / cnt_f_n1_3_all
            Cells(26, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n1_4_all = 0 Then
            Cells(27, i) = 0
        Else
            Cells(27, i) = cnt_f_n1_4_liq * 100 / cnt_f_n1_4_all
            Cells(27, i).NumberFormat = "#,##0.00"
        End If


        If cnt_f_n2_1_all = 0 Then
            Cells(34, i) = 0
        Else
            Cells(34, i) = cnt_f_n2_1_liq * 100 / cnt_f_n2_1_all
            Cells(34, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n2_2_all = 0 Then
            Cells(35, i) = 0
        Else
            Cells(35, i) = cnt_f_n2_2_liq * 100 / cnt_f_n2_2_all
            Cells(35, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n2_3_all = 0 Then
            Cells(36, i) = 0
        Else
            Cells(36, i) = cnt_f_n2_3_liq * 100 / cnt_f_n2_3_all
            Cells(36, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n2_4_all = 0 Then
            Cells(37, i) = 0
        Else
            Cells(37, i) = cnt_f_n2_4_liq * 100 / cnt_f_n2_4_all
            Cells(37, i).NumberFormat = "#,##0.00"
        End If


        If cnt_f_n3_1_all = 0 Then
            Cells(44, i) = 0
        Else
            Cells(44, i) = cnt_f_n3_1_liq * 100 / cnt_f_n3_1_all
            Cells(44, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n3_2_all = 0 Then
            Cells(45, i) = 0
        Else
            Cells(45, i) = cnt_f_n3_2_liq * 100 / cnt_f_n3_2_all
            Cells(45, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n3_3_all = 0 Then
            Cells(46, i) = 0
        Else
            Cells(46, i) = cnt_f_n3_3_liq * 100 / cnt_f_n3_3_all
            Cells(46, i).NumberFormat = "#,##0.00"
        End If
        If cnt_f_n3_4_all = 0 Then
            Cells(47, i) = 0
        Else
            Cells(47, i) = cnt_f_n3_4_liq * 100 / cnt_f_n3_4_all
            Cells(47, i).NumberFormat = "#,##0.00"
        End If

Next i

        cnt_f_1_liq = 0
        cnt_f_2_liq = 0
        cnt_f_3_liq = 0
        cnt_f_4_liq = 0
        cnt_f_1_all = 0
        cnt_f_2_all = 0
        cnt_f_3_all = 0
        cnt_f_4_all = 0

        cnt_f_n0_1_liq = 0
        cnt_f_n0_2_liq = 0
        cnt_f_n0_3_liq = 0
        cnt_f_n0_4_liq = 0
        cnt_f_n0_1_all = 0
        cnt_f_n0_2_all = 0
        cnt_f_n0_3_all = 0
        cnt_f_n0_4_all = 0

        cnt_f_n1_1_liq = 0
        cnt_f_n1_2_liq = 0
        cnt_f_n1_3_liq = 0
        cnt_f_n1_4_liq = 0
        cnt_f_n1_1_all = 0
        cnt_f_n1_2_all = 0
        cnt_f_n1_3_all = 0
        cnt_f_n1_4_all = 0

        cnt_f_n2_1_liq = 0
        cnt_f_n2_2_liq = 0
        cnt_f_n2_3_liq = 0
        cnt_f_n2_4_liq = 0
        cnt_f_n2_1_all = 0
        cnt_f_n2_2_all = 0
        cnt_f_n2_3_all = 0
        cnt_f_n2_4_all = 0

        cnt_f_n3_1_liq = 0
        cnt_f_n3_2_liq = 0
        cnt_f_n3_3_liq = 0
        cnt_f_n3_4_liq = 0
        cnt_f_n3_1_all = 0
        cnt_f_n3_2_all = 0
        cnt_f_n3_3_all = 0
        cnt_f_n3_4_all = 0

End Sub

The “Next Without For” Compile Error is a very common compile-time error in Excel VBA. It implies that a Next statement must always have a preceding For statement that matches it. If a Next statement is used without a corresponding For statement, this error is generated.

Let us look at some most common causes of the error and way to fix and avoid them.

Example 1: If statement without a corresponding “End If” statement

Sub noEndIf()
    Dim rng As Range
    Dim cell As Range

    Set rng = ActiveSheet.Range("B1:B10")
    For Each cell In rng
    If cell.Value = 0 Then
    cell.Interior.color = vbRed
    Else
    cell.Interior.color = vbGreen
    Next cell

End Sub


Every If statement (and If Else Statement) must have a corresponding End If statement along with it. As you can see in the above code, End If is missing after the Else block, causing the error. The right way to do it is



  


                       
  




Sub withEndIf()
    Dim rng As Range
    Dim cell As Range

    Set rng = ActiveSheet.Range("B1:B10")
    For Each cell In rng
        If cell.Value = 0 Then
            cell.Interior.color = vbRed
        Else
            cell.Interior.color = vbGreen
        End If
    Next cell

End Sub

Example 2: Incorrect sequence of End If and Next statements
Sub incorrectEndIf()
    Dim rng As Range
    Dim cell As Range

    Set rng = ActiveSheet.Range("B1:B10")
    For Each cell In rng
    If cell.Value = 0 Then
    cell.Interior.color = vbRed
    Else
    cell.Interior.color = vbGreen
    Next cell
    End If
End Sub

Here, the End If statement is not placed correctly causing overlapping as shown below:
For
If
Next
End If
The entire If statement (including, If, Else and End If statements), must be placed withing the For…Next block as shown below
Sub correctEndIf()
    Dim rng As Range
    Dim cell As Range

    Set rng = ActiveSheet.Range("B1:B10")
    For Each cell In rng
        If cell.Value = 0 Then
            cell.Interior.color = vbRed
        Else
            cell.Interior.color = vbGreen
        End If
    Next cell

End Sub

Example 3: With statement has a corresponding End With Statement missing
Sub noEndWith()

    Dim counter As Integer
    Dim lastRow As Integer
    Dim fName As String, lName As String, fullName As String

    lastRow = 10

    For counter = 1 To lastRow

    With ActiveSheet
    fName = .Cells(counter, 1).Value
    lName = .Cells(counter, 2).Value

    fullName = fName & " "  lName
    'Further processing here

    Next counter

End Sub

Just like an If statement, the With statement should also have a corresponding End With statement, without which error will be thrown. The working example:
Sub withEndWith()
    Dim counter As Integer
    Dim lastRow As Integer
    Dim fName As String, lName As String, fullName As String

    lastRow = 10

    For counter = 1 To lastRow

        With ActiveSheet
            fName = .Cells(counter, 1).Value
            lName = .Cells(counter, 2).Value
        End With

        fullName = fName  " "  lName
        'Further processing here

    Next counter

End Sub

Example 4: Overlapping For and If Else statement
Say, in the example below, you want to do some processing only if a condition is false. Else you want to continue with the next counter of the For loop
Sub overlapping()
    Dim counter As Integer
    For counter = 1 To 10
        If Cells(counter, 1).Value = 0 Then
            Next counter
        Else
            'Do the processing here
        End If
    Next counter

End Sub

Note: as in other programming languages, VBA does not have a continue option for a loop. When the control of the program reaches the first “Next counter” statement after the If statement — it finds that there is a Next statement within the If statement. However, there is no corresponding For statement within this If Block. Hence, the error.
So, you can use one of the two solutions below:
Simply remove the “next” statement after If



  


                       
  




Sub solution1()
    Dim counter As Integer
    For counter = 1 To 10
        If Cells(counter, 1).Value = 0 Then
            'Simply don't do anything here
        Else
            'Do the processing here
        End If
    Next counter

End Sub

OR
Not the if condition and place your code there. Else condition is not required at all
Sub solution2()
    Dim counter As Integer
    For counter = 1 To 10
        If Not Cells(counter, 1).Value = 0 Then
            'Not the if condition and
            'Do the processing here
        End If
    Next counter
End Sub

The bottom line is that the “If, Else, End If statement block” must be completely within the For loop.
Avoiding the Next without For error by using standard coding practices
The best way to avoid this error is to follow some standard practices while coding.
1. Code indentation: Indenting your code not only makes it more readable, but it helps you identify if a loop / if statement / with statement are not closed properly or if they are overlapping. Each of your If statements should align with an End If, each For statement with a Next, each With statement with an End With and each Select statement with an End Select
2. Use variable name with Next:  Though the loop variable name is not needed with a next statement, it is a good practice to mention it with the Next statement.
So, change
 Next 
to
 Next counter 
This is particularly useful when you have a large number of nested for Loops.
3. As soon as you start a loop, write the corresponding end statement immediately. After that you can code the remaining statements within these two start and end statements (after increasing the indentation by one level).
If you follow these best practices, it is possible to completely and very easily avoid this error in most cases.
See also: Compile Error: Expected End of Statement

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