Питон выдает ошибку restart

3 ответа

Лучший ответ

Обычно в режиме ожидания (если он не запущен с -n) выполняется код пользователя в подпроцессе пользователя. Строка RESTART означает, что подпроцесс был перезапущен. Независимо от того, как запускается Idle (без -n), это происходит либо при выборе Shell → Restart Shell Cntl + F6, либо в Run → Run Module F5.

RESTART также возникает, если пользовательский процесс вылетает из программы. Если вы запускаете Idle из командной строки (python -m idlelib или ... idlelib.idle в 2.x, там может появиться сообщение об ошибке, но это не происходит с вашей программой.

Я запустил вашу программу с помощью 3.4.3 после первой замены строки ввода конкретным назначением (которое вы должны были сделать перед публикацией)

x = list(reversed(range(1000)))

(Этот выбор является наихудшим вариантом для многих алгоритмов сортировки).

Я ничего не видел в командном окне, но видел сообщение Windows, которое python.exe прекратил работать. Поскольку Idle все еще работает, это относится к процессу ошибок.

Сокращение 1000000 до 10000 ничего не изменило. Выход из предисловия рекурсии в 1000 приводит к длительной трассировке.

Traceback (most recent call last):
  File "C:Programspython34tem.py", line 33, in <module>
    fun(L,L_,c)
  File "C:Programspython34tem.py", line 29, in fun
    return fun(x,lista,c)
....
  File "C:Programspython34tem.py", line 29, in fun
    return fun(x,lista,c)
  File "C:Programspython34tem.py", line 18, in fun
    for i in range(len(x)-1):
RuntimeError: maximum recursion depth exceeded in comparison

Уменьшение списка до размера 100 не изменило результат. У вас бесконечный цикл, который вам нужно предотвратить.

Вы код не похожи на версии quicksort, с которыми я знаком. Возможно, вам следует рассмотреть определение алгоритма.

Однако эта строка для j в диапазоне (i + 1, я + 2): выглядит как ошибка, когда она повторяется только один раз, с j = i+1. Как бы то ни было, программа работает одинаково, если вы замените ее на эту строку и разделите следующие строки.

В любом случае условие завершения x[i]<=x[j] and c==len(x)-2 не выполняется. Я предлагаю начать с коротким списком с помощью нескольких элементов и добавить от заявлений для печати в fun, чтобы увидеть, как значения отклоняются от того, что вы ожидаете. Вы также можете попробовать выполнить свой алгоритм вручную.

I was writing a code for my test in idle python.When i run the module it's just keeps restarting.
This is my code:

sins = 0
check = input()
if check == "check_sins":
        print(sins)
second = input("Ok,you can start when you are ready,type Im Ready! if you want to start the game")
print("Welcome to How smart are you test")
name = input("What's your name? ")
print(name)
if name == "Dimitrije":
    print("Nice to meet you Dimitrije")
start = input("Ready to start the test: ")
if start == "Yes":
    print("A) Gorillaz")
    print("B) Alvin and the chipmunks")
    print("C) Despacito 2")
    print("D) Who are you even")
    q1 = input("Which was the first animated band ever created? ")
    a1 = "A) Gorillaz"
    b1 = "B) Alvin and the chipmunks"
    c1 = "C) Despacito 2"
    d1 = "D) Who are you even"
    if q1 == "A" or q1 == "a":
        print("You are right,adding 10 sins for that")
        sins += 10
    else:
            sins = sins - 10
    print("A) Milan")
    print("B) ")
    print("")
    print("")
else:
    print(second)
    if start == "Im ready!":
        print("Ok,let's start")
    print(q1)
    print(a1)
    print(b1)
    print(c1)
    print(d1)
    if q1 == "A":
        print("You are right,adding 10 sins for that")
        sins = sins + 10
Note:I started learning python yesterday and sins are just a refrence of the youtube channel name called CinemaSins.So don't judge.

First off, no judgment! :)

I just want to get some more details from you. 
1) How are you running your program?
2) How far into your program do you get?
3) What are you passing in as values for your Input() calls?

Im running as a idle python(when im in editor,i run the module)
I get like in 3 days(if you asked when did i get into the program,english is not my first language)
For my input calls i put a string so that player knows what to answer to.
I hope i answered your questions for details.(I don't understand some things when someone says like '	PyArg_ParseTupleAndKeywords' or something like that,im 12 year old so i don't understand some issues)

Maybe you could describe what it looks like when it restarts? Or take a screenshot and share it so we can see what is happening?

In IDLE, Run Module, F5, is a shortcut, in a sense, for saving the file to filename, switching to a terminal or console window, such as Command Prompt on Windows, and entering 'python -i filename'.  The -i means 'switch it interactive mode after running the file'.  When you are done, and close the window, you can switch back to the editor.

The IDLE Shell more-or-less simulates Python's interactive mode.  When you hit F5, a separator line is added, like 
=================== RESTART: F:Pythonatem.py =====================
to indicate that Shell reinitialized itself and is now running your program.  This is completely normal and intended.  When your program finishes, Shell will display '>>> '.

Please try to read the IDLE doc, which is available on the Help menu as 'IDLE Help'.  You can ask about using Python and IDLE on python-list.   Always mention the Python version and operating system you are using.

You program has a bug.  In the 'else' section, it tries to print q1 without q1 being defined.

If a program has a severe bug that caused the Python executing your code to crash, Shell will restart with a line that does not have a filename, like
======================== RESTART ========================
This is hard to bring about and is also not an IDLE bug.

Well the error looks like this

===== RESTART: F:Python Shell LearningGamesHow smart are you Test.py =====
i think it's normal but it won't show '>>> '.I will see what i can do,but thanks for some help.

Again, that RESTART line is NOT an error.  IDLE's prompt is not displayed until your program is completely done.  It initially pauses on the second line 'check = input()', waiting for user input.

Start with a one-line file:

print('Hello to my game')

Run that and you will see the prompt.

Thanks Terry J. ReedyTerry.

resolution: not a bug
stage: resolved

assignee: terry.reedy
components:
+ IDLE

Работал на ноутбуке Samsung 300E5X-U02 (процессор Intel Pentium B960), Windows 10 x64. Программа на Python 2.7.6 x64, запускаю через Python IDLE, при помощи Selenium (webdriver = chromedriver) парсил сайты. Все работало без нареканий. Недавно купил другой ноутбук ACER Aspire E5-553G-15CK (процессор AMD A12 9700P), установил ту же Windows 10 x64, тот же Python 2.7.6 x64, но Python IDLE периодически начал самопроизвольно перезапускаться, причем, как оказалось, даже если программа выкинула ошибку и я не закрывал Python Shell, за ночь получается 3-4 перезапуска (сообщения о рестарте идут друг за другом). Аналогично на Python 2.7.12 x64 и на Python 3.5.2 x64. В чем может быть причина, неужели это из-за процессора?

=============================== RESTART: Shell ===============================
>>> 
=============================== RESTART: Shell ===============================
>>> 
=============================== RESTART: Shell ===============================
>>> 
=============================== RESTART: Shell ===============================
>>>

Ответы
1

Другие вопросы по теме

When the python script crashes, the program is not running anymore, therefore the script cannot execute more lines of code.

You have 2 options:

1. Make sure your python script doesn’t crash, which is very much recommended. You can do this by handling the exceptions thrown by your program.

Option 1

I assume you are new to python, so here is an example of a python script that handles an exception calls the same function again.

from time import sleep

def run_forever():
    try:
        # Create infinite loop to simulate whatever is running
        # in your program
        while True:
            print("Hello!")
            sleep(10)

            # Simulate an exception which would crash your program
            # if you don't handle it!
            raise Exception("Error simulated!")
    except Exception:
        print("Something crashed your program. Let's restart it")
        run_forever() # Careful.. recursive behavior
        # Recommended to do this instead
        handle_exception()

def handle_exception():
    # code here
    pass

run_forever()

1. If you want to restart the python script you would need another python script (assuming you want to do this with python) that checks if the process is still alive and if not then run it again with python.

Option 2

This is the script that starts another python script called ‘test.py’ via the command python test.py.
Make sure you have the right file path, if you put the scripts in the same folder, you usually don’t need the full path and only the script name.

Notably, make sure that command ‘python‘ is recognized by your system, it could in some cases by ‘python3’

script_starter.py

from subprocess import run
from time import sleep

# Path and name to the script you are trying to start
file_path = "test.py" 

restart_timer = 2
def start_script():
    try:
        # Make sure 'python' command is available
        run("python "+file_path, check=True) 
    except:
        # Script crashed, lets restart it!
        handle_crash()

def handle_crash():
    sleep(restart_timer)  # Restarts the script after 2 seconds
    start_script()

start_script()

In case you are interested in the code I used for the test file: ‘test.py’, I post it here.

test.py

from time import sleep
while True:
    sleep(1)
    print("Hello")
    raise Exception("Hello")

import numpy as np

def main():
    np.load('File.csv')

for i in range(1, 10):
    try:
        main()
    except Exception as e:
        print e
        print 'Restarting!'
        main()

3 ответа

Лучший ответ

import numpy as np

def main():
    np.load('File.csv')

for i in range(1, 10):
    try:
        main()
    except Exception as e:
        print e
        print 'Restarting!'
        continue
    else:
        break

import numpy as np
import sys
sys.setrecursionlimit(10)  # set recursion depth limit


def main():
    try:
        a = np.load('file.csv')
        if a:
            return a
    except Exception as e:
        return main()

result = main()
print result

import numpy as np
import time

def main():
    np.load('file.csv')

start = time.time()
stop = start + 5
attempts = 0
result = 'failed'

while True:
    if time.time()<stop:
        try:
            main()
        except Exception as e:
            attempts += 1
            print e
            time.sleep(0.1) # optional
            print 'Restarting!'
            continue
        else:
            result = 'succeeded'
    print 'Connection %s after %i attempts.' % (result, attempts)
    break

# retry.py

import time

def retry(f, seconds, pause = 0):
    start = time.time()
    stop = start + seconds
    attempts = 0
    result = 'failed'

    while True:
        if time.time()<stop:
            try:
                f()
            except Exception as e:
                attempts += 1
                print e
                time.sleep(pause)
                print 'Restarting!'
                continue
            else:
                result = 'succeeded'
        print '%s after %i attempts.' % (result, attempts)
        break

import numpy as np
from retry import retry

def main():
    np.load('file.csv')

retry(main, 5, 0.1)

class RetryTest():
    def __init__(self, succeed_on = 0, excp = Exception()):
        self.succeed_on = succeed_on
        self.attempts = 0
        self.excp = excp
    def __call__(self):
        self.attempts += 1
        if self.succeed_on == self.attempts:
            self.attempts = 0
        else:
            raise self.excp

retry_test1 = RetryTest(3)
retry(retry_test1, 5, 0.1)
# succeeded after 3 attempts.
retry_test2 = RetryTest()
retry(retry_test2, 5, 0.1)
# failed after 50 attempts.