Ошибка main должен возвращать int

This my main function:

void main(int argc, char **argv)
{
    if (argc >= 4)
    {
        ProcessScheduler *processScheduler;
        std::cout <<
            "Running algorithm: " << argv[2] <<
            "nWith a CSP of: " << argv[3] <<
            "nFilename: " << argv[1] <<
            std::endl << std::endl;

        if (argc == 4)
        {
            processScheduler = new ProcessScheduler(
                argv[2],
                atoi(argv[3])
            );
        }
        else
        {
            processScheduler = new ProcessScheduler(
                argv[2],
                atoi(argv[3]),
                atoi(argv[4]),
                atoi(argv[5])
            );
        }
        processScheduler -> LoadFile(argv[1]);
        processScheduler -> RunProcesses();

        GanntChart ganntChart(*processScheduler);
        ganntChart.DisplayChart();
        ganntChart.DisplayTable();
        ganntChart.DisplaySummary();

        system("pause");

        delete processScheduler;
    }
    else
    {
        PrintUsage();
    }
}

The error I get when I compile is this:

Application.cpp:41:32: error: ‘::main’ must return ‘int’

It’s a void function how can I return int and how do I fix it?

C++ requires main() to be of type int.

answered Nov 2, 2016 at 14:14

The error message is trying to tell you that main must return int.

i.e. Line 21 should be int main() and at the end of your program you must return 0; // obviously only if the program executed successfully

return 0; is superfluous — main (and only main) returns 0 by default when the end of the function is reached.

For people who are new to programming who may not know that it is a good habbit to get into. Also, although somwhat a small amount, it makes the code more readable.