Invalid shorthand property initializer ошибка js

Pallab GangulyPallab Ganguly

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answered Mar 22, 2021 at 5:12

Change the = to : to fix the error.

var makeRequest = function(message) {<br>
 var options = {<br>
  host: 'localhost',<br>
  port : 8080,<br>
  path : '/',<br>
  method: 'POST'<br>
 }

In options object you have used «=» sign to assign value to port but we have to use «:» to assign values to properties in object when using object literal to create an object i.e.»{}» ,these curly brackets. Even when you use function expression or create an object inside object you have to use «:» sign.
for e.g.:

    var rishabh = {
        class:"final year",
        roll:123,
        percent: function(marks1, marks2, marks3){
                      total = marks1 + marks2 + marks3;
                      this.percentage = total/3 }
                    };

john.percent(85,89,95);
console.log(rishabh.percentage);

here we have to use commas «,» after each property.
but you can use another style to create and initialize an object.

var john = new Object():
john.father = "raja";  //1st way to assign using dot operator
john["mother"] = "rani";// 2nd way to assign using brackets and key must be string

answered Mar 3, 2019 at 15:49

Use : instead of =

see the example below that gives an error

app.post('/mews', (req, res) => {
if (isValidMew(req.body)) {
    // insert into db
    const mew = {
        name = filter.clean(req.body.name.toString()),
        content = filter.clean(req.body.content.toString()),
        created: new Date()
    };

That gives Syntex Error: invalid shorthand proprty initializer.

Then i replace = with : that’s solve this error.

app.post('/mews', (req, res) => {
if (isValidMew(req.body)) {
    // insert into db
    const mew = {
        name: filter.clean(req.body.name.toString()),
        content: filter.clean(req.body.content.toString()),
        created: new Date()
    };

answered Dec 24, 2019 at 17:36

I’m trying to validate a pin using the following function

function validate(num){
  num.length === 4 || num.length === 6 ? {
    regex = /d+/,
    regex:test(num)
  } 
  :
  false
}

however I’m getting this error and I can’t figure out why

    /home/runner/index.js:3
    regex = /d+/,
    ^^^^^^^^^^^^^

SyntaxError: Invalid shorthand property initializer

As others have pointed out, you can’t put statements in conditional expressions (or any other expression, either), you can only put expressions.

The error you’re getting is because it thinks you’re trying to write an object literal, but you can’t have assignments inside object literals.

You can use a normal if statement:

if (num.length == 4 || num.length == 6) {
    var regex = /d+/;
    return regex.test(num);
} else {
    return false;
}

But there’s no need for the conditional at all, you can test the length in the regexp itself.

function validate(num) {
    return /^d{4}$|^d{6}$/.test(num);
}

answered Dec 20, 2019 at 23:24

While I cannot recommend such here, it is important to keep in mind that a function expression can be used in an expression context. This is done all the time, such as for callbacks, and the same concept is transferable elsewhere..

Here is a minimal conversion of the original (which maintains as many of the original’s bugs and other features, except where they caused parse errors) showing a function expression. This specific case is also called an «IIFE».

function validate(num){
  return num.length === 4 || num.length === 6
   ? (function() {
       let regex = /d+/; 
       return regex.test(num);
     })()
   : false;
} 

answered Dec 20, 2019 at 23:51

I’m trying to validate a pin using the following function

function validate(num){
  num.length === 4 || num.length === 6 ? {
    regex = /d+/,
    regex:test(num)
  } 
  :
  false
}

however I’m getting this error and I can’t figure out why

    /home/runner/index.js:3
    regex = /d+/,
    ^^^^^^^^^^^^^

SyntaxError: Invalid shorthand property initializer

As others have pointed out, you can’t put statements in conditional expressions (or any other expression, either), you can only put expressions.

The error you’re getting is because it thinks you’re trying to write an object literal, but you can’t have assignments inside object literals.

You can use a normal if statement:

if (num.length == 4 || num.length == 6) {
    var regex = /d+/;
    return regex.test(num);
} else {
    return false;
}

But there’s no need for the conditional at all, you can test the length in the regexp itself.

function validate(num) {
    return /^d{4}$|^d{6}$/.test(num);
}

answered Dec 20, 2019 at 23:24

While I cannot recommend such here, it is important to keep in mind that a function expression can be used in an expression context. This is done all the time, such as for callbacks, and the same concept is transferable elsewhere..

Here is a minimal conversion of the original (which maintains as many of the original’s bugs and other features, except where they caused parse errors) showing a function expression. This specific case is also called an «IIFE».

function validate(num){
  return num.length === 4 || num.length === 6
   ? (function() {
       let regex = /d+/; 
       return regex.test(num);
     })()
   : false;
} 

answered Dec 20, 2019 at 23:51