import numpy as np
with open('matrix.txt', 'r') as f:
x = []
for line in f:
x.append(map(int, line.split()))
f.close()
a = array(x)
l, v = eig(a)
exponent = array(exp(l))
L = identity(len(l))
for i in xrange(len(l)):
L[i][i] = exponent[0][i]
print L
-
My code opens up a text file containing a matrix:
1 2
3 4
and places it in listxas integers. -
The list
xis then converted into an arraya. -
The eigenvalues of
aare placed inland the eigenvectors are placed inv. -
I then want to take the exp(a) and place it in another array
exponent. -
Then I create an identity matrix
Lof whatever lengthlis. -
My for loop is supposed to take the values of
exponentand replace the 1’s across the diagonal of the identity matrix but I get an error sayinginvalid index to scalar variable.
What is wrong with my code?
asked Nov 27, 2012 at 22:42
1
exponent is a 1D array. This means that exponent[0] is a scalar, and exponent[0][i] is trying to access it as if it were an array.
Did you mean to say:
L = identity(len(l))
for i in xrange(len(l)):
L[i][i] = exponent[i]
or even
L = diag(exponent)
?
answered Nov 27, 2012 at 22:45
NPENPE
478k105 gold badges939 silver badges1006 bronze badges
0
IndexError: invalid index to scalar variable happens when you try to index a numpy scalar such as numpy.int64 or numpy.float64. It is very similar to TypeError: 'int' object has no attribute '__getitem__' when you try to index an int.
>>> a = np.int64(5)
>>> type(a)
<type 'numpy.int64'>
>>> a[3]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: invalid index to scalar variable.
>>> a = 5
>>> type(a)
<type 'int'>
>>> a[3]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'int' object has no attribute '__getitem__'
answered Sep 19, 2013 at 20:36
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AkavallAkavall
80.3k49 gold badges205 silver badges247 bronze badges
1
In my case, I was getting this error because I had an input named x and I was creating (without realizing it) a local variable called x. I thought I was trying to access an element of the input x (which was an array), while I was actually trying to access an element of the local variable x (which was a scalar).
answered Apr 7, 2020 at 19:46
nbronbro
14.7k29 gold badges107 silver badges192 bronze badges
IndexError is an exception error in python you get when you try to index the list or array and the length of it is out of the range. Most programmers get this type of error while accessing the element from the array or list. In this tutorial, you will know how to solve the IndexError: invalid index to scalar variable error in a simple way.
Why does the IndexError: invalid index to scalar variable Error occurs?
Most of the time you will get the error when you are trying to wrongly access the element of the array. For example, you have created a variable of scalar type but you are indexing the element like the two or more dimensions.
Let’s understand it deeply. Suppose I have created a scalar value in numpy. If I am trying to access it wrongly then I will get the invalid index to scalar variable error.
You will get the error when you will run the below lines of code.
import numpy as np
x = np.int32(10)
print(x[0])
Output

In the same way, you will get the invalid index to the scalar variable when you try to access the element of the numpy array like it is a multi-dimensional array.
import numpy as np
array = np.array([1,2,3,4])
print(array[0][0])
Output

Solution of the invalid index to scalar variable Error
The solution to this indexerror is very simple. Make sure to identify the type of the array whether it is a scalar and single-dimensional or multi-dimensional array.
Taking the same example as the above, you don’t have to use the index in the square bracket to access the value. You can access directly using the variable name only.
import numpy as np
x = np.int32(10)
print(x)
Output
10
And if it is an array of single-dimensional then don’t use the square bracket two times to access the element. Just use the single square bracket with the index inside it.
import numpy as np
array = np.array([1,2,3,4])
print(array[0])
Output
1
Conclusion
In the name itself IndexError you can get the idea of why you are getting the error. Most of cases the error are due to wrong accessing of the element. The error index to a scalar variable is the same. To solve this error you have first identified the element is of scalar or another dimension and then use the correct way to access it.
I hope you have liked this tutorial. If you have any queries then you can contact us for more help.
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Indexing is one of the most important concepts when we talk about large data with a linear data structure. It is equally essential to understand how we have to use indexes to feature our data and deal with data for actual use. In this article, we will deal with the topic of solving invalid indexes to the scalar variable.
What is an «invalid index to scalar variable» error?
It is a compile-time error that occurs when the programmer does not put the correct index position or dimension-tier ( [][] ) while accessing any list value from the list. Dimension tier is the number of square brackets we have to use with the variable or identifier’s name to fetch any particular value from that list. If we talk about Python, it is essential to know how the square brackets work while fetching any particular value from a list or nested list. If the programmer does any kind of mistake, then we might encounter this «invalid index to scalar variable” error.
Let us now Practically see this in action:
If you have a situation with a code
import numpy as np
val = np.array([[2, 3], [6, 4], [9, 7]])
print("The value is ", val[0][1][2])
And you want to display a specific value from the NumPy array created using the nested list values.

You can see, the program is showing the invalid index to scalar variable error. It is because the NumPy array defined here has a dimension of two. This means, only two indices are enough to represent any particular value from the NumPy array created from a nested list. But here, within the print(), we are using three tier indexing which is not appropriate.
This is the reason why this program is showing such error.
How to Solve it?
There are two ways of solving such issues.
1st way:
import numpy as np
val = np.array([[2, 3], [6, 4], [9, 7]])
print("The value is ", val[0], val[1], val[2])

Explanation:
Doing this will make the Python interpreter understand that each of the values within the pair of square brackets represent index 0, 1, and 2 respectively. So, calling them directly using the single tier value will fetch the lists residing inside the ndarray.
2nd way:
import numpy as np
val = np.array([[2, 3], [6, 4], [9, 7]])
print("The value is ", val[1][0]) // val[1st sq. bracket][2nd sq. bracket]

This is the other way of doing this. Here, we are using two-tier since the NumPy array is a two dimensional array of data nested in a single layer. This will fetch the value 6 because the first square bracket indicates the [2, 3] => index 0, [6, 4] => index 1, and [9, 7] => index 2
The second square bracket represent the values inside it. [6 => sub index 0, 4 => sub index 1]
Conclusion:
To solve the invalid index to scalar variable error, programmers must keep a close eye at writing the index value and number of square brackets. If the number of square brackets is not appropriate or an anomaly occurs (the declaration and definition have two-dimensional NumPy array that uses a 3-tier indexing), then there is a possibility of index scalar variable error. Hence, it is also essential to know the different ways of representing and accessing NumPy arrays data from a defined variable.
The “indexerror: invalid index to scalar variable.” error mostly appears because of the usage of scalar instead of an array. There are other reasons for this error described in this article. Experts’ ideas and tips included in this article will help you quickly fix this error. Keep reading to gather all the information to fix this issue.
Contents
- Why Are You Getting Indexerror: Invalid Index To Scalar Variable?
- – Indexing Into a Non-iterable in Pandas
- – Invalid Index of Y
- – Wrong Use of Indices
- – Use of Scalar Instead of Array
- – Indexing a Numpy Scalar
- – Local Variable
- – Version of Numpy
- – Index a Scalar
- – The Version of the cv2 Module
- How To Fix the Error
- – Indexing Into a Non-iterable in Pandas
- – Wrong Use of Indices
- – Coding Example of Solving the Indices Issue in Numpy
- – Use of Scalar Instead of Array
- – Indexing a Numpy Scalar
- – Local Variable
- – Version of Numpy
- – Index a Scalar
- – Coding Example of Solving the “Indexerror: Invalid Index To Scalar Variable.” Error
- – The Version of the cv2 Module
- FAQ
- – What Are Scalar Variables in Python?
- – What Is the Difference Between Scalar Variables, Lists, and an Array?
- Conclusion
Why Are You Getting Indexerror: Invalid Index To Scalar Variable?
There could be many reasons for this error to appear. Let’s find out what those reasons are.
– Indexing Into a Non-iterable in Pandas
If you are working on Pandas and getting this error at the line “result.append(RMSPE(np.expm1(y_train[testcv]), [y[1] for y in y_test]))”, the cause of this invalid index error pandas in your case could be that you are indexing into a scalar, which is a non-iterable value.
– Invalid Index of Y
If you are using ‘1’ in y, you should know that ‘1’ is not a avoid index of y. Because if someone checks from their code, they will find if your y contains the index they are trying to access. So here, the index would be ‘1’.
– Wrong Use of Indices
You might be using indices where they are not supposed to be used. Suppose you are working in a for loop, and you have an iteration, and each element of that loop, if it is a scalar, has no index. If you use indices where each element is a single variable, empty array, or scalar but not a list or array, you might face that error.
– Use of Scalar Instead of Array
If you are working with matrix and arrays in NumPy and getting this error, the reason for this error could be like you might have mistakenly used a 1D array or scalar where you were supposed to use an array.
– Indexing a Numpy Scalar
Suppose you are trying to index a Numpy scalar such as NumPy.int64 or NumPy.float64; you can get the “indexerror: invalid index to scalar variable” error. This error is very similar to the “TypeError: ‘int’ object has no attribute ‘__getitem__,’ that often appears when you index an int.
– Local Variable
This error can create a problem for you if you make a local variable with an input variable of the same name as the local variable. Every time you try to access any element of a local variable, you would be trying to access the element of the local variable. The real problem happens when you have an array as an input variable and a scalar as a local variable.
– Version of Numpy
Many developers face this error, and there is nothing wrong with their code. This error could also appear if you are not using the correct version of Numpy. Due to some bugs, sometimes the version you are using doesn’t provide the desired output.
– Index a Scalar
Keep in mind that you can’t index a scalar or a number. It should be either a list or an array.
This is one of the most common causes of that error when developers
– The Version of the cv2 Module
If you are working on the CV2 module in Python, the leading cause could be not having the correct version of the CV2 module. Some developers have faced this error while working in Python. You also might experience that your code doesn’t run on Jupyter notebook but run on google collab.
How To Fix the Error
We covered all the possible causes of this error. Let’s find out the solutions to these causes.
– Indexing Into a Non-iterable in Pandas
Make sure that when you are calling [y for y in test], you are already iterating over the values, and that’s how you will get a single value in ‘y’. The main issue in most cases is [y[1] for y in y_test]. Here you can expand your list comprehension if you want to append each y in y_test to the results. Then you can make it like the following.
[result.append(…,y) for y in y_test]
You can even gor for a loop like the following.
for y in y_test:
results.append(…,y)
– Wrong Use of Indices
If you have doubts about the usage of indices, make sure you use indices at the correct positions. Let’s understand this by the following example.
– Coding Example of Solving the Indices Issue in Numpy
import numpy as np
val = np.array([[1,2], [3, 4], [7, 5])
print(“The value is ”, val[0][1][2])
You would want a specific value from the NumPy array, but you get the “indexerror: invalid index to scalar variable” error. Because the defined array is 2D, only two indices are required for any particular value, but here three-tier is are being used, which is the cause of this error. Here you have two solutions.
Solution One:
You can modify your code as follows to avoid error.
import numpy as np
val = np.array([[1,2], [3, 4], [7, 5])
print(“The value is ”, val[0], val[1], val[2])
If you do that, the python interpreter will understand that the values inside of each pair of brackets represent indexes 0,1 and 2. This is how the list will be fetched residing inside the ndarray as you are calling them directly by the single-tier value.
Solution Two:
import numpy as np
val = np.array([[1,2], [3, 4], [7, 5])
print(“The value is ”, val[1][0])
As the NumPy array is a two-dimensional array, we use a two-tier here. This is how to fix an invalid index to scalar variables.
– Use of Scalar Instead of Array
If you are stuck in NumPy with arrays and matrices and getting this error, you must first make sure you don’t use a scalar of a 1D array instead of a 2D array.
– Indexing a Numpy Scalar
To fix this error in this case, you need to fix your code. Here somewhere, you would think that the array has one more dimension than it has.
– Local Variable
You must verify that the variable you are using should have a unique name that you don’t repeat in your code to avoid this issue.
– Version of Numpy
If you are sure that there is no mistake in your code, it must be the problem with the version of Numpy you are using. To fix this issue, you can upgrade or downgrade the version.
– Index a Scalar
If you are indexing a scalar, you will get that error. Here you need to understand a few things before trying to fix it, such that if you are using any variable like x[0] or x[1], then what is the x there? If any variable being used is called a function, what is that variable? If the value is being passed to any other variable, what is that variable? Does the original variable, x[0] or x[1], support all such indexing? Let’s understand this by the code example below:
– Coding Example of Solving the “Indexerror: Invalid Index To Scalar Variable.” Error
First of all we will write a code
import numpy as np
x=np.array([[2,3],[4,5],[5,6]])
print(x[0][0][1])
Here is our code, and when we run this code, we will get the error.
Output:
Traceback (most recent call last)
File “<string>”, line 3,in <module>
indexerror: invalid index to scalar variable.
To solve this error, the first thing we need to do is to make sure whether the indexing is correct or not. Suppose we are making any mistake while indexing, such as using a 2D array where a 3D array should be used or vice versa; we need to correct it. And then, as we use the same code with the correct indexing, you will no longer face that error. The accurate index would be as follows:
And you will get the expected answer as follows:
– The Version of the cv2 Module
If you are getting this error because of not having the correct version of the CV2 module, you must be using a version of CV2 that doesn’t support the CUDA. To get rid of this error, you need to use the version of the CV2 module that supports CUDA, as it gives you a 2-D array.
FAQ
– What Are Scalar Variables in Python?
Scalar variables in python are those variables that contain only one value.
– What Is the Difference Between Scalar Variables, Lists, and an Array?
Scalar variables contain only one variable, while a list is a variable that can hold a series of values. So when you need to assign more than one corresponding value to a single variable, you can create a list variable. An array is very similar to a list, but an array can store elements of different data types, whereas the list can only store elements of the same data type.
Conclusion
Let’s sum up what we learned today:
- The leading causes of this error are using wrong indices, using a scalar where it shouldn’t be used, or indexing a scalar.
- The number of indices you use should be correct.
- Make sure that the names of local and input variables don’t match.
We understood why we got the “indexerror: invalid index to scalar variable” error, all the causes of that error along with solutions. You will not face any difficulty facing this error as you know how to solve it. Use this article as your guide when you reencounter this error.
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- What Is the
IndexError: invalid index to scalar variablein Python - Fix the
IndexError: invalid index to scalar variablein Python - Fix the
IndexError: invalid index to scalar variablein 2D Numpy Arrays

The IndexError is too common, specifically when you are new to numpy arrays. The index is the location of elements in an array.
It is easy when we have a simple array, but when the dimensions increase, the array becomes complex too. As the dimensional of an array increases, then indices increase too.
Let’s say when you have a simple array, you will require one index to access the elements, and in two-dimensional arrays, you will require two indices.
Example of the one and two-dimensional arrays:
One_D = [1,2,3,4,5]
print(One_D[0]) #--> 1
two_D = [[1,2,3],
[4,5,6]]
print(two_D[1][0]) #--> 4
Output:
What Is the IndexError: invalid index to scalar variable in Python
The IndexError: invalid index to scalar variable in Python occurs when you misuse the indices of a numpy array. Let’s say we have one-dimensional arr.
import numpy as npy
arr = npy.array([1,2,3,4,5])
print(arr[0][1])
Output:
IndexError: invalid index to scalar variable.
In the above example, the array arr requires only one index, but rather we are trying to access the elements with two indices [0][1], which doesn’t exist. Hence, it throws the IndexError: invalid index to scalar variable.
Fix the IndexError: invalid index to scalar variable in Python
Fixing the IndexError is too simple and easy; the error itself is self-explanatory; it tells us that the issue is with the index and you are providing an invalid index to access the element.
We need to provide the right index according to the nature of the array. Let’s fix the IndexError of the above program.
import numpy as npy
arr = npy.array([1,2,3,4,5])
print(arr[3])
Output:
Fix the IndexError: invalid index to scalar variable in 2D Numpy Arrays
When you understand the working of an array, then two-dimensional is not a big deal to understand indices, and you are good to go.
Let’s take an example of a 2-D numpy array.
import numpy as npy
# creating a 2-D array
arr = npy.array([[1,2,3],
[4,5,6]])
# with 2 rows and 3 columns
print(arr.shape)
# arr[2nd row] [3rd column]
print(arr[1][2])
#print(arr[1][2][3]) --> IndexError: invalid index to scalar variable.
Output:
In this example, we have a 2-D array arr whose shape is (2,3) means it has two rows and 3 columns, and we know that in computer programming languages, indices start with 0, and it means 1.
So the indices arr[1][2] means accessing the array arr element at the 2nd row and 3rd column, which is 6.
And again, if you provide invalid indices like arr[1][2][3] 3 indices instead of 2 to the arr array, this will throw the IndexError: invalid index to scalar variable because that location does not exist in the arr array.
Этот код генерирует ошибку:
IndexError: invalid index to scalar variable.
В строке: results.append(RMSPE(np.expm1(y_train[testcv]), [y[1] for y in y_test]))
Как это исправить?
import pandas as pd
import numpy as np
from sklearn import ensemble
from sklearn import cross_validation
def ToWeight(y):
w = np.zeros(y.shape, dtype=float)
ind = y != 0
w[ind] = 1./(y[ind]**2)
return w
def RMSPE(y, yhat):
w = ToWeight(y)
rmspe = np.sqrt(np.mean( w * (y - yhat)**2 ))
return rmspe
forest = ensemble.RandomForestRegressor(n_estimators=10, min_samples_split=2, n_jobs=-1)
print ("Cross validations")
cv = cross_validation.KFold(len(train), n_folds=5)
results = []
for traincv, testcv in cv:
y_test = np.expm1(forest.fit(X_train[traincv], y_train[traincv]).predict(X_train[testcv]))
results.append(RMSPE(np.expm1(y_train[testcv]), [y[1] for y in y_test]))
testcv это:
[False False False ..., True True True]
2 ответа
Лучший ответ
Вы пытаетесь проиндексировать в скалярное (не повторяемое) значение:
[y[1] for y in y_test]
# ^ this is the problem
Когда вы вызываете [y for y in test], вы уже перебираете значения, поэтому вы получаете одно значение в y.
Ваш код такой же, как попытка сделать следующее:
y_test = [1, 2, 3]
y = y_test[0] # y = 1
print(y[0]) # this line will fail
Я не уверен, что вы пытаетесь получить в свой массив результатов, но вам нужно избавиться от [y[1] for y in y_test].
Если вы хотите добавить каждый y в y_test к результатам, вам необходимо расширить понимание списка до чего-то вроде этого:
[results.append(..., y) for y in y_test]
Или просто используйте цикл for:
for y in y_test:
results.append(..., y)
9
Monkpit
6 Окт 2015 в 20:37
По сути, 1 не является допустимым индексом y. Если посетитель приходит из своего собственного кода, он должен проверить, содержит ли его y индекс, к которому он пытается получить доступ (в этом случае индекс равен 1).
0
gies0r
20 Окт 2019 в 17:57
Python Numpy arrays are indexed using integers, starting from 0 for the first element.
Use the negative indices to access elements from the end of the array.
Only use the scaler integer value to access the index of an array; otherwise, you will face IndexError, which we will discuss in this article.
The IndexError: invalid index to scalar variable occurs when you are trying to access an element of an array or list using incorrect index position or dimension-tier ( [][] ).
If an array is a single dimensional, one index([]) is sufficient to represent that array.
If an array is two-dimensional, two indices ([][]) are sufficient to represent a 2D array.
If an array is three-dimensional, three indices ([][][]) are sufficient to represent a 3D array.
Now, if you try to access an element from a 2D array using three indices([][][]), you will get the IndexError: invalid index to scalar variable error.
The following code will generate the IndexError.
import numpy as np
value = np.array([[21, 19], [11, 18], [21, 46]])
print("The value is ", value[0][1][2])
Output
IndexError: invalid index to scalar variable.
The above code will generate the “IndexError: invalid index to scalar variable” error because the value variable is a 2D array with shape (3,2), and it only has two indices to access the elements, the first one for rows, and the second one for columns.
We are trying to access an additional index by using value[0][1][2] where the first index 0 is for rows, the second index 1 is for columns, and the third index 2 is not valid because the value is a 2D array.
Let’s see how to resolve it.
How to Fix IndexError: invalid index to scalar variable
Two easy ways to fix IndexError in Python.
- Access the element using only two indices, value [0][1].
- Access the element using single indice, value[0], value[1], value[2].
Method 1: Using two indices
To access the specific value from a two-dimensional array, use the value[0][1] syntax.
import numpy as np
value = np.array([[21, 19], [11, 18], [21, 46]])
element = value[0][1]
print("The element is:", element)
Output
In the above code, the single element is accessed using the indices (0,1), which corresponds to the element in the first row and second column of the 2D array.
This code won’t raise the “IndexError: invalid index to scalar variable” error because the indices (0,1) are valid indices for the 2D array.
Method 2: Using single Indice
To access the specific array from a two-dimensional array, use the value[0] syntax.
import numpy as np
value = np.array([[21, 19], [11, 18], [21, 46]])
element_first = value[0]
element_second = value[1]
element_third = value[2]
print("The first element is:", element_first)
print("The second element is:", element_second)
print("The third element is:", element_third)
Output
The first element is: [21 19]
The second element is: [11 18]
The third element is: [21 46]
In the above code, the element_first is accessed using the index 0, which corresponds to the element in the first row of the 2D array.
The element_second is accessed using index 1, and element_third is accessed using index 2.
The code won’t raise the “IndexError” error because the index 0, 1, and 2 are valid indices for the 2D array.
Conclusion
In a two-dimensional array, you can either access the specific array or specific elements from the arrays.
Use the syntax arr[index] to access the specific array from the two-dimensional array.
Use the syntax array[row][column] to access the specific element from the two-dimensional array.
Что значит иметь индекс ошибки скалярной переменной? питон
import numpy as np
with open('matrix.txt', 'r') as f:
x = []
for line in f:
x.append(map(int, line.split()))
f.close()
a = array(x)
l, v = eig(a)
exponent = array(exp(l))
L = identity(len(l))
for i in xrange(len(l)):
L[i][i] = exponent[0][i]
print L
Мой код открывает текстовый файл, содержащий матрицу: 1 2 3 4
и помещает его в список «x» в виде целых чисел. Затем список «x» преобразуется в массив «a». Собственные значения «a» помещаются в «l», а собственные векторы помещаются в «v». Затем я хочу взять exp (a) и поместить его в другой массив «exponent». Затем я создаю единичную матрицу любой длины «l» и называю матрицу «L». Цикл «Мой» должен принимать значения «экспоненты» и заменять 1 по диагонали идентификационной матрицы, но я получаю сообщение об ошибке «Недействительный индекс для скалярной переменной». Что не так с моим кодом?
28 нояб. 2012, в 00:24
Поделиться
Источник
exponent — это 1D-массив. Это означает, что exponent[0] является скаляром, а exponent[0][i] пытается получить к нему доступ, как если бы он был массивом.
Вы имели в виду сказать:
L = identity(len(l))
for i in xrange(len(l)):
L[i][i] = exponent[i]
или даже
L = diag(exponent)
?
NPE
27 нояб. 2012, в 23:49
Поделиться
IndexError: invalid index to scalar variable происходит, когда вы пытаетесь индексировать скаляр numpy, например numpy.int64 или numpy.float64. Он очень похож на TypeError: 'int' object has no attribute '__getitem__', когда вы пытаетесь индексировать int.
>>> a = np.int64(5)
>>> type(a)
<type 'numpy.int64'>
>>> a[3]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: invalid index to scalar variable.
>>> a = 5
>>> type(a)
<type 'int'>
>>> a[3]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'int' object has no attribute '__getitem__'
Akavall
19 сен. 2013, в 21:46
Поделиться
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