Общие советы :
1) все данные (и виды платежей) — в одной плоской таблице (без каких-либо объединений ячеек) на одном(!) листе. Разделы «по счету», «по счетчику(по факту)» и «контроль» — это просто дополнительные столбцы справа.
2) вверху оставьте 10 строк для формул «итого», они всегда видны, т.к. область с формулами» закреплена»
3) Долг и переплата — это всегда одна строка, переплату можно ставить красным (формат ячейки — Отрицательное красным)
4) Из-за перерасчетов задним числом и смены тарифов — «помесячные итоги» не так полезны для анализа, как «нарастающий с начала года» или вообще «с начала времен». Я бы внес все квитки с начала года, добавил к январскому сумму долга/переплаты.
5) Т.к. квитанция состоит всегда из 5 строк (Эл.Д, Эл.Н, ХВС, Вывоз ТКО, Утилизация ТКО) — то сразу их скопировать на 2 года вперед. Т.к. тариф меняется условного говоря «раз в полгода» и долго действует — сослаться формулами апреля — на март итд. И когда тариф эл. энергии станет не 2,83 а 4 — просто в том месяце перебиваем формулу на значение 4.
6) Нужно освоить функцию =СУММЕСЛИ(). Формула, которая суммирует все Дн. киловатты (по счету, счетчику и разницу) с начала года будет выглядеть так: =СУММЕСЛИ(Вид;’ЭлДень’;ПоСчету)
=СУММЕСЛИ(Вид;’ЭлДень’;ПоСчетчику)
=СУММЕСЛИ(Вид;’ЭлДень’;Отклон)
Чтобы можно было так легко писать и понимать формулы — нужно дать имена столбцам (точнее их диапазонам с 11-й по, скажем, по 71-строку, вперед на 5 лет). Для этой цели часто делают «официальную» шапку таблицы и ниже, через 1 пустую строку — дублируют её же краткой одной строкой «полей», в ней все слова без пробелов «Электроэнергия День кВт.ч» -> «ЭлДень». Понятности это не уменьшит, а вот скорость написания формулы вырастет пятикратно. Имена диапазонов можно тогда не создавать — Calc сам поймет где находится столбец «ЭлДень», с какой ячейки начинается и где заканчивается.
7) Самым левым столбцом делают «Период», вводят дату, скажем 31.01.18, 28.02.18. а в формате ячейки — Январь 18, Февраль 18 итд. После включения автофильтра на строке «полей», отделенной от «шапки» пустой строкой — появятся значки Автофильтра и возможность легко отбирать нужный период или нужный вид платежа в Автофильтре.
8) Чтобы автосуммировать видимое (прошедшее фильтр) — нужно освоить функцию =ПРОМЕЖУТОЧНЫЕ.ИТОГИ(9;СЧЕТ)
Полученная плоская таблица обладает громадным плюсом, она все-в-одном, логически целостна. Если захочется сделать по ней отчет — изучаем Сводные таблицы и диаграммы и делаем их на 2-м листе. Но даже просто =ПРОМЕЖУТОЧНЫЕ.ИТОГИ() даст вам информацию о среднем, максимальном, минимальном значении чего угодно за любой период, который выбирается Автофильтром.
Я плачу раз в полгода (ненавижу этот процесс и очереди, т.к. УК до сих пор работает только через ГРЦ-кассы, безнал никак, руководы УК по доброй российской традиции в федеральном розыске), — то оплату я ввожу одной строкой «между» квитанций (заплатил 10/03 — 45 тыс. руб.) Формула у меняя сама делит сумму одного платежа (45 тыс. руб.) на 108 отдельных чисел (по видам платежей). Это достигается суммированием накопленного долга с остатками долга и пени, пропорциональным делением. УК делает все точно так же, и когда с ними спорю — нахожу понимание. Разбивать 45 тр. на 6 квитанций х 6 видов платежей х 3 вида (недоимка/пеня/перерасчет) = 108 цифр — считаю пустой тратой времени. Учетные программы в УК и ТСЖ делают точно так же.
-
Torieth
- Posts: 10
- Joined: Wed Apr 29, 2015 2:23 pm

[Solved] Error Integrity constraint violation — no parent SY
Hi, I’m new to this forum and to Base and that may be why I’m struggling so much to do anything. I have learned a lot in this forum without having any account. So thank you, guys, for the help already given.
I have a problem. I’m trying to make a form out of a table with a field named «ID_REQUEST» wich is a Primary key, autocomplete BIGINT from another table with all requests so far.
I can’t fill in the ID_REQUEST due to it’s randomness, but, I have two fields that can. They are REQUEST_NUMBER and REQUEST_ENTRY, they, combined, answer for a unique request. Then I have another problem… A single request may have or not multiple products and there is one resgistry for each product, repeating the combination REQUEST_NUMBER and REQUEST_ENTRY.
I tried the following to select a request from a list box:
Data field is set to: ID_REQUEST
The list box content is obtained by a SQL query like this one: SELECT DSITINCT «REQUEST_NUMBER» || ‘/’ || «REQUEST_ENTRY» FROM «TAB_REQUEST»
When I test this form, it gives me an error called
Integrity constraint violation — no parent SYS_FK_115 table: TAB_REQUEST in statement [INSERT INTO «TAB_PRODUCTION» ( «DATE»,»ID_COLAB»,»ID_REQUEST»,»ID_SETOR»,»OBS»,»PRODUCTION») VALUES ( ?,?,?,?,?,?)]
How can I solve this?
Last edited by Torieth on Wed Apr 29, 2015 6:54 pm, edited 1 time in total.
Open Office 4.1.1
Windows XP SP 3
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Villeroy
- Volunteer
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- Joined: Mon Oct 08, 2007 1:35 am
- Location: Germany
Re: Error Integrity constraint violation — no parent SYS_FK_
Post
by Villeroy » Wed Apr 29, 2015 3:58 pm
Your struggling has nothing to do with Base.
Your database table has a foreign key or two which means that you can not put any value into this field unless it has an equivalent value in the primary key of the referenced table.
I guess that you are going to insert a concatenated value
«REQUEST_NUMBER» || ‘/’ || «REQUEST_ENTRY» FROM «TAB_REQUEST»
into your foreign key where just a valid request_number is possible since the request number existst in the TAB_REQUEST but not the concatenated string.
And like so many others you think that a combo box is helpful but a combo box is just a simple text box with some auto-complete functionality.
Convert the combo to a list box and continue here: viewtopic.php?f=13&t=76600&p=349166#p349166
Please, edit this topic’s initial post and add «[Solved]» to the subject line if your problem has been solved.
Ubuntu 18.04 with LibreOffice 6.0, latest OpenOffice and LibreOffice
-
Torieth
- Posts: 10
- Joined: Wed Apr 29, 2015 2:23 pm
Re: Error Integrity constraint violation — no parent SYS_FK_
Post
by Torieth » Wed Apr 29, 2015 4:33 pm
Thanks for your answer, Villeroy. I’m a bit confused… I’m actually using a list box already as the combo box kept showing zeros in all fields.
Here are the tables I’m using
Production table (the onde I need to make form from)
Name: TAB_PRODUCTION
Fields:
- ID_PRODUCTION
- DATE
- SECTOR
- COLABORATOR
- QUANTITY
- REQUEST
- OBSERVATION
Request table
Name: TAB_REQUEST
Fields:
- ID_REQUEST
- REQUEST_NUMBER
- REQUEST_ENTRY
- Several fields containing details…
Sector table
Name: TAB_SECTOR
Fields:
- ID_SECTOR
- SECTOR
- Several fields containing details…
Colaborator table
Name: TAB_COLABORATOR
Fields:
- ID_COLABORATOR
- COLABORATOR
- Several fields containing details…
The fields REQUEST_NUMBER and REQUEST_ENTRY are together a single Request, I need that whenever I set a REQUEST_NUMBER and REQUEST_ENTRY combination into the form it gives me back always the same ID_REQUEST, no matter wich one. I thought that the «DISTINCT» modifier into the «SELECT» would give me only the first result for each REQUEST_NUMBER and REQUEST_ENTRY combination.
Apparently, I got that wrong and I think I’m getting the forms wrong altogether. I mean, into the list box there is the list I need to be and I can select the combination of REQUEST_NUMBER and REQUEST_ENTRY the way I imagined it. Why does it not track back the ID_REQUEST that gave that combination out?
Open Office 4.1.1
Windows XP SP 3
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Villeroy
- Volunteer
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Re: Error Integrity constraint violation — no parent SYS_FK_
Post
by Villeroy » Wed Apr 29, 2015 4:43 pm
Your current list box selects only one concatenated field. A list box can use 2 fields, a visible one and hidden one to be written.
Following my recipe for a 2-column list box:
Linked field: REQUEST (a foreign key field of this form’s row set)
Source Type: SQL (or Query)
Source: SELECT DSITINCT «REQUEST_NUMBER» || ‘/’ || «REQUEST_ENTRY» AS «Visible», ID_REQUEST FROM «TAB_REQUEST» ORDER BY «Visible» (or the name of the query with this statement)
Bound Field: 1 (which is the second field, the primary key of the referred table TAB_REQUEST. The visible field would be 0)
Please, edit this topic’s initial post and add «[Solved]» to the subject line if your problem has been solved.
Ubuntu 18.04 with LibreOffice 6.0, latest OpenOffice and LibreOffice
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Torieth
- Posts: 10
- Joined: Wed Apr 29, 2015 2:23 pm
Re: Error Integrity constraint violation — no parent SYS_FK_
Post
by Torieth » Wed Apr 29, 2015 6:53 pm
It worked!
Thank you so much!
Then, it gave me some new doubts… xP
I think the list box will always show only the first field in the query, right? So, I can add as much fields as I wish to order it properly or is there a limit? I mean, look at this table:
Colaborator table
Name: TAB_COLABORATOR
Fields:
- ID_COLABORATOR
- COLABORATOR
- ID_SECTOR
- Several fields containing details…
I need to fill in the colaborator list box with the name of them, now it’s like this:
SELECT DISTINCT COLABORATOR , ID_COLABORATOR FROM TAB_COLABORATOR
It’s working fine, but, I’d like to order this list by sector and then by colaborator. Is it possible? I tried this:
SELECT DISTINCT COLABORATOR , ID_SECTOR, ID_COLABORATOR FROM TAB_COLABORATOR ORDER BY ID_SECTOR ASC, COLABORATOR ASC
It apparently works, but it shows the first query item in the list box and independently if a choose another item, whenever I change the focus from the list box it will come back to the first item.
Another thing is, I have several details from de request, after selected I’d like to show the request description as a way of confirmation. Can I do that somehow?
Open Office 4.1.1
Windows XP SP 3
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Villeroy
- Volunteer
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- Location: Germany
Re: [Solved] Error Integrity constraint violation — no paren
Post
by Villeroy » Wed Apr 29, 2015 9:01 pm
You don’t need to select a column to order by.
SELECT A, B FROM X ORDER BY C works just fine.
or even
SELECT A, B FROM X ORDER BY (SELECT M FROM Y WHERE Y.A = X.Z)
which orders by a another table’s field using some related field(s) between the tables.
Please, edit this topic’s initial post and add «[Solved]» to the subject line if your problem has been solved.
Ubuntu 18.04 with LibreOffice 6.0, latest OpenOffice and LibreOffice
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Villeroy
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Re: [Solved] Error Integrity constraint violation — no paren
Post
by Villeroy » Thu Apr 30, 2015 2:13 pm
Just compose a query with 2 columns, one visible and one with the other table’s primary key to be used as this form’s foreign key. The sort order should be ascending by the visible column because the alphabetical order makes it easier to spot things while typing.
The content of the visible field can be anything which helps to lookup the right primary key.
Please, edit this topic’s initial post and add «[Solved]» to the subject line if your problem has been solved.
Ubuntu 18.04 with LibreOffice 6.0, latest OpenOffice and LibreOffice
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Torieth
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- Joined: Wed Apr 29, 2015 2:23 pm
Re: [Solved] Error Integrity constraint violation — no paren
Post
by Torieth » Thu Apr 30, 2015 3:16 pm
Villeroy, thank you for all this answers!
I have so many questions. Is there anywhere I can ask several newbie questions? I feel like this thread is not an optimal place to do it…
By field, I meant a form field, not a base field. I’d like to use the data inserted in the fields to filter the next form field query
And, I’d like to know why some list boxes show up the first query item and others don’t? I’d like all of them to be void initially.
Open Office 4.1.1
Windows XP SP 3
I’m struggling to find what I’m doing wrong with my query.
I did not create the database but here is the structure :
3 TABLES :
vehicule : brand, motor, price, name, id
option : id, description, price
vehicule_option : id_vehicule, id_option
I guess that vehicule_option has 2 foreign keys but I can not find the problem with my addings.
Here’s my code which first part works fine :
public boolean create(Vehicule v){
String query = "INSERT INTO vehicule (MARQUE, MOTEUR, PRIX, NOM) VALUES (";
query += v.getMarque().getId() + ", "
+ v.getMoteur().getId() + ", "
+ v.getPrix() + ", '"
+ v.getNom() + "');";
for (Option o : v.getOptions()){
query += "INSERT INTO vehicule_option (id_vehicule, id_option) VALUES ("
+ v.getId() + ", " + o.getId() + ");";
}
try{
Statement state = this.connect.createStatement();
ResultSet rs = state.executeQuery(query);
} catch (SQLException e){
e.printStackTrace();
}
return true;
}
So, what I’m doing here is basically INSERT two values into the right columns.
It gives me the following exception :
java.sql.SQLIntegrityConstraintViolationException: integrity constraint violation: foreign key no parent; SYS_FK_10132 table: VEHICULE_OPTION
at org.hsqldb.jdbc.JDBCUtil.sqlException(Unknown Source)
at org.hsqldb.jdbc.JDBCUtil.sqlException(Unknown Source)
at org.hsqldb.jdbc.JDBCStatement.fetchResult(Unknown Source)
at org.hsqldb.jdbc.JDBCStatement.executeQuery(Unknown Source)
at fr.ocr.sql.DAOVehicule.create(DAOVehicule.java:35)
at fr.ocr.ihm.AddCarDialogBox$1.actionPerformed(AddCarDialogBox.java:151)
at javax.swing.AbstractButton.fireActionPerformed(Unknown Source)
at javax.swing.AbstractButton$Handler.actionPerformed(Unknown Source)
at javax.swing.DefaultButtonModel.fireActionPerformed(Unknown Source)
at javax.swing.DefaultButtonModel.setPressed(Unknown Source)
at javax.swing.plaf.basic.BasicButtonListener.mouseReleased(Unknown Source)
at java.awt.Component.processMouseEvent(Unknown Source)
at javax.swing.JComponent.processMouseEvent(Unknown Source)
at java.awt.Component.processEvent(Unknown Source)
at java.awt.Container.processEvent(Unknown Source)
at java.awt.Component.dispatchEventImpl(Unknown Source)
at java.awt.Container.dispatchEventImpl(Unknown Source)
at java.awt.Component.dispatchEvent(Unknown Source)
at java.awt.LightweightDispatcher.retargetMouseEvent(Unknown Source)
at java.awt.LightweightDispatcher.processMouseEvent(Unknown Source)
at java.awt.LightweightDispatcher.dispatchEvent(Unknown Source)
at java.awt.Container.dispatchEventImpl(Unknown Source)
at java.awt.Window.dispatchEventImpl(Unknown Source)
at java.awt.Component.dispatchEvent(Unknown Source)
at java.awt.EventQueue.dispatchEventImpl(Unknown Source)
at java.awt.EventQueue.access$500(Unknown Source)
at java.awt.EventQueue$3.run(Unknown Source)
at java.awt.EventQueue$3.run(Unknown Source)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.ProtectionDomain$1.doIntersectionPrivilege(Unknown Source)
at java.security.ProtectionDomain$1.doIntersectionPrivilege(Unknown Source)
at java.awt.EventQueue$4.run(Unknown Source)
at java.awt.EventQueue$4.run(Unknown Source)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.ProtectionDomain$1.doIntersectionPrivilege(Unknown Source)
at java.awt.EventQueue.dispatchEvent(Unknown Source)
at java.awt.EventDispatchThread.pumpOneEventForFilters(Unknown Source)
at java.awt.EventDispatchThread.pumpEventsForFilter(Unknown Source)
at java.awt.EventDispatchThread.pumpEventsForHierarchy(Unknown Source)
at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
at java.awt.EventDispatchThread.run(Unknown Source)
Caused by: org.hsqldb.HsqlException: integrity constraint violation: foreign key no parent; SYS_FK_10132 table: VEHICULE_OPTION
at org.hsqldb.error.Error.error(Unknown Source)
at org.hsqldb.Constraint.getException(Unknown Source)
at org.hsqldb.Constraint.checkInsert(Unknown Source)
at org.hsqldb.StatementDML.performIntegrityChecks(Unknown Source)
at org.hsqldb.StatementDML.insertSingleRow(Unknown Source)
at org.hsqldb.StatementInsert.getResult(Unknown Source)
at org.hsqldb.StatementDMQL.execute(Unknown Source)
at org.hsqldb.Session.executeCompiledStatement(Unknown Source)
at org.hsqldb.Session.executeDirectStatement(Unknown Source)
at org.hsqldb.Session.execute(Unknown Source)
... 40 more
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Description
This error message appears in NeoBase.
The full text will be something like this:
Integrity constraint violation — no parent 4, table: Table A in statement [ALTER TABLE «Table A» ADD FOREIGN KEY («field name A») REFERENCES «Table B» («field name B»)
Cause
It occurs when you are trying to relate Table A to Table B by means of the two fields named. The field from table A («field name A») is called a Foreign Key (FK). Any field that links into another table (Table B, in this case) is called a Foreign Key. Remember that every table must have its own Primary Key (PK)
It means that there is data in field name A on one of the records in Table A that does not match any of the data in field name B on the records in Table B.
Solution
Check your data. Make certain that every record in table A has a value in field name A that can be matched to an instance of field name B.
An example:
| Table A = Purchases | field name A = customer number |
| Table B = Customers | field name B = customer ID |
| customer number | customer ID |
| 0 | 3 |
| 1 | 4 |
| 2 | 5 |
The problem with the data frequently occurs when test data is entered by hand and it’s hard to keep track of the automatically created Primary Keys.
Comments
binwiederhier
added this to the
Release 0.1 (developer alpha) milestone
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…; CleanupMergeDatabaseFilesScenarioTest / testIssue58_2 produces a very similar problem
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…UNK constraint exception
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Mar 24, 2014
…UNK constraint exception
binwiederhier
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…tead of merge-then-purge)
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…58 (testIssue58_4); breaks all previous repositories !!
This was referenced
Aug 2, 2014
Okay, I’m probably doing something really obviously wrong here but I’m under a lot of (largely unrelated) stress and just cannot see where the issue I’m having stems from.
I am making a database to manage my books and ebooks which are spread over several locations. I have five tables currently
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‘Books’ (with fields for Book ID [auto-value int], Author [int], Title [varchar], Format [Int], Location [int], Series [int], Comments [varchar].
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‘Author’ (with an ID field [auto-value int] and a field for the actual Author’s name [varchar]
-
‘Format’ (with an ID field [auto-value int] and a field for the name of the location [varchar]
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‘Location’ (with an ID field [auto-value int] and a field for the name of the location [varchar])
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‘Series’ (with an ID field [auto-value int] and a field for the actual name of the series [varchar]
I have each field in ‘Books’ related to the ID field of the relevant table (i.e. Books.Author is related to Author.AuthorID, etc) and I want to make a form for inputting books. I’ve been trying to do one using the Author table as the main table and only bringing in the Author Name field from it and adding the Books table as a subfield that pulls in all but the Author and Book ID fields. I am having three issues. The smallest of the two is that whenever I click into a box in the form while testing it the default text of ‘None’ in the Series box changes to 0 and anything entered into that field changes to 0 as soon as you click away. Not sure if its just not working right or if it is returning the Series ID instead as there are no series in the series table right now.
The other small issue is that when I fill in the form to test it the Author name I enter stays in the box, it adds it to the Author table just fine but for some reason the field shows the name initially instead of being blank. I don’t know why it’s doing that or how to set it so it stays blank instead.
The major problem is that whenever I fill in the form and then hit the save I get the following error and it cannot save the entry.
Integrity Constraint Violation — no parent SYS_FK_129 table: Author in Statement [INSERT INTO «Books» («Author», «Comments», «Format», «Location», «Series», «Title») VALUES (?, ?, ?, ?, ?, ?)]
and I don’t know what it means or how to even begin to go about fixing it.
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Integrity constraint violation — no parent
Creator:
Anonymous
Created:
2010-04-13
Updated:
2014-01-19
-
I have the following tables:
CREATE MEMORY TABLE APPLICATIONCI( PRODUCTNAME VARCHAR(255) NOT NULL, PRODUCTVERSION VARCHAR(255) NOT NULL, VENDOR VARCHAR(255) NOT NULL, DESCRIPTION VARCHAR(255), LICENSE_ID INTEGER, PRIMARY KEY(PRODUCTNAME,PRODUCTVERSION,VENDOR)) CREATE MEMORY TABLE MACHINECI( SERIAL VARCHAR(255) NOT NULL PRIMARY KEY, CPUTYPE VARCHAR(255) NOT NULL, ECN VARCHAR(255) NOT NULL, MAKE VARCHAR(255) NOT NULL, MEMORY VARCHAR(255) NOT NULL, MODEL VARCHAR(255) NOT NULL, NUMBEROFCPUS INTEGER NOT NULL) CREATE MEMORY TABLE APPLICATIONINSTALLATION( SERIAL VARCHAR(255) NOT NULL, VENDOR VARCHAR(255) NOT NULL, PRODUCTNAME VARCHAR(255) NOT NULL, PRODUCTVERSION VARCHAR(255) NOT NULL, CONSTRAINT FKDBBC178AA1D77B74 FOREIGN KEY(PRODUCTNAME,PRODUCTVERSION,VENDOR) REFERENCES APPLICATIONCI(PRODUCTNAME,PRODUCTVERSION,VENDOR)) ALTER TABLE APPLICATIONINSTALLATION ADD CONSTRAINT FKDBBC178AEAFDF5D4 FOREIGN KEY(SERIAL) REFERENCES MACHINECI(SERIAL)And when I try to:
INSERT INTO APPLICATIONINSTALLATION (SERIAL,PRODUCTNAME,PRODUCTVERSION,VENDOR) VALUES ('sd34-fsd4-ff23-fdsf','foo','baa','foobaa')I get the following HSQL error:
Integrity constraint violation — no parent FKDBBC178AA1D77B74 table: APPLICATIONCI / Error Code: -177 / State: 23000This is occurring in HSQL 1.8.0 packed in JBoss 5.1
Any ideas?
-
You need an existing row in MACHINECI with the same value in the SERIAL column as the value you are attempting to insert into the other table.
-
Fredt,
Thanks for the reply. Sorry, I should have been more explicit. The values for both MACHINECI and APPLICATIONCI already exist by the time I try to insert a row in APPLICATIONINSTALLATION.
INSERT INTO APPLICATIONCI (VENDOR,PRODUCTNAME,PRODUCTVERSION,DESCRIPTION,LICENSE_ID) VALUES ('foobaa','foo','baa','bla bla',2) INSERT INTO MACHINECI (SERIAL,CPUTYPE,ECN,MAKE,MEMORY,MODEL,NUMBEROFCPUS) VALUES ('sd34-fsd4-ff23-fdsf','Intel i7','hj234hty','IBM','192Gb','x3850',48)
-
I’ve just tested this with 1.8.1.2 and it works fine if I insert the following line before your statement.
INSERT INTO APPLICATIONCI (VENDOR,PRODUCTNAME,PRODUCTVERSION,DESCRIPTION,LICENSE_ID) VALUES (‘sd34-fsd4-ff23-fdsf’,’foo’,’baa’,’bla bla’,2)Please check again. In case there is an issue with the particular jar, you can use the 1.8.1.2 jar instead of the one that is in the JBoss 5.1 package.
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Last time I just inserted a modified version of the two insert statements you posted. Noticed they are required before your original INSERT problem. So this time I ran all three inserts exactly as you reported. They work fine.
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Fredt,
Yes, you are correct. I’ve quickly changed my configuration to PostgreSQL and I got the same problem. The error was way more informative and I was able to fix it. Basically, the tables are actually being created by EJB3 entities and when generated the following was not correct:
CREATE MEMORY TABLE APPLICATIONINSTALLATION( SERIAL VARCHAR(255) NOT NULL, VENDOR VARCHAR(255) NOT NULL, PRODUCTNAME VARCHAR(255) NOT NULL, PRODUCTVERSION VARCHAR(255) NOT NULL, CONSTRAINT FKDBBC178AA1D77B74 FOREIGN KEY(VENDOR,PRODUCTNAME,PRODUCTVERSION) REFERENCES APPLICATIONCI(PRODUCTNAME,PRODUCTVERSION,VENDOR)) The error is in the order of the FK fields: FOREIGN KEY(VENDOR,PRODUCTNAME,PRODUCTVERSION) should read FOREIGN KEY(PRODUCTNAME,PRODUCTVERSION,VENDOR) like I have on my side test.The fix was to have the order correct in the Entity bean
... @JoinTable(name="ApplicationInstallation", joinColumns={@JoinColumn(name="serial")}, inverseJoinColumns={@JoinColumn(name="productName"),@JoinColumn(name="productVersion"),@JoinColumn(name="vendor")}) ...I’ve tested the fix once again on HSQL and everything is working fine.
Again, thank you for your help.
-
OK. btw HSQLDB version 2.0 supports FK declarations with alternative column orders.
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If you have an error integrity constraint in Oracle on your system, I hope this guide will help you.
ORA-02291 is usually followed by “Integrity message constraint – parent not found”. This means that you tried to reference this table using the primary key, but the posts you specified did not match the primary key type.
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APAR Status
Closed Due To Error.
Error Description
Oracle Enterprise considers some constraint violations to be fatalErrors - Most restrictions for both are reported as an integrity error.sqlcode-1. There are several that fall outside the scope:ORA-02290: limits will bethis is the test condition(string.The string)hurtreason: inserted values don't do itsatisfy the given check constraint.Action: N insert which values violateforced it.ORA-02291: integrity constraint (string-string)wounded foundReason: Guardian Key of the foreign Key value is the sameno primary key value.Action: remove the Australian key or add one that suits you.primary key.Restrictionora-02292: lifetime values (string.string)wounded - foundReason: abstinence of the child. Attempting to remove the value "Mom", "Important" or "Dad".which dependency had on a foreign key.Action: Remove dependencies from duplicate content then parent first orDisable restriction.They must be created to be in the SQL list.oraUpsert code. which, c, according to experts, are more likely to be sent to the failure servicewhich cause a fatal error for encoding.
Local Solution
Issue Overview
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We******************************************************* ******************************
Problem: It's Impossible To Reproduce The Look Of This Art. However, A New Patch Is Coming Out.The Last Code That Solved The Problem On The Client's Site.
Workaround
Comments
Information-apar
Apar Sys Is Routed In One Or More Of The Following Ways:
The
APAR Is Redirected By The System To One Or More Of The Following Devices:
Correct Information
What are integrity constraints in Oracle?
Fixed Deposit Ratio Name
WIS DATA
Fixed Component ID
5724Q36DS
Applicable Components
PSN Levels R751
UP
APAR Number
JR28935
Name Of Component To Report
What is Sqlstate 23000 integrity constraint violation?
Error Database error: SQLSTATE[23000]: Violation of the integrity constraint itself means that your hug ‘s_id’ could be a primary key and therefore the system does not allow it to be null.
WIS DATA
Id Of The Specified Component

5724Q36DS
Disclaimer Reported
751
Status
CLOSED
PE
Not PE
HIPER
Which action could cause an integrity constraint error?
No HIPER
Special Attention
No clarification
Filing Date
2008-04-09
Closing Date
2008-10-29
Last Year Of Release
2008-10-29
The following example shows a bug, and there are a few fixes we can handle living in Oracle:
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![]()
Error
-- Create
SQL> main table create cart testprimary(primary key id, name varchar2(10));
The table has been created.
-- Table Foregin create SQL> table
Create testforeign(f_id f_name number, varchar2(10), number, foreign key(p_id) p_id recommendation testprimary(id) );
the table has been created.
insert
What is integrity constraint violated?
Constraints occur when an insert, update, or delete notification violates a primary key, a key, an external unique evaluation or constraint, or another index.
— Data in your two tables
Insert sql> basic test parameters (1, ‘RAM’);
1 short period created.
SQL> testprimary to values(2,’RAM2′);
Insert 1 Creates scratches.
Pastesql> in Testprimary(3,’RAM3′);
Feed value 1 created.
happened![]()
— error:
SQL> remove from where id testprimary is 1 testprimary;
remove from where=detection 1
*
Internet Integrity Discipline, ERROR 1:
ora-02292: (TEST.SYS_C008202) broken – child record
found
Reason
If we try to successfully delete the data from the maintables, we will first remove the mention table (child table)
When creating foreign keys, owners can specify an ON DELETE clause to indicate why rows behind the parent table are being deleted.
ON DELETE If cascading: a row from the parent table is frequently deleted, everything from the child table row related to this short period will be deleted.
ON DELETE SET NULL: and when the row of the parent row is deleted, all rows from the reference to table 1 to the row of this external content key are set to NULL.
How do you resolve integrity constraint violated parent key not found?
chain) parent – dishonored key not found. ORA-02291 Errors. They are related to the fact that the fundamental foreign instrument does not have a primary corresponding key market price. To fix this error, you need to remove the foreign key or add an important matching key. primary key. Violations.
Option 1: Correct information about table search restrictions in data
1. Find foreign table key name and column name from invalid constraint name:
col for multiple owner table names a15
Collar for a15
column name column associated with a15
primary owner pass for a10
main constraint name col a15
select for a.constraint_type,a.owner,a.table_name,b.column_name,a.r_owner "PrimaryOwner",a.All_constraints r_constraint_name "primaryconstraintname" from all_cons_columns a where
A b.CONSTRAINT_NAME = b.CONSTRAINT_NAME and a.constraint_name is OWNER 'sys_c008202';
c PrimaryOwn table_name column_name PrimaryConstrai- ————– ————— ————— ——————-R —— TEST FOREIGN TEST P_ID TEST SYS_C0082012. The best primary key of the table has now been found.
Note. Use a longer query exit constraint name and enter the enforcement information key.
col for table name a15
Branded collar for working with a15
column name column for a15
main owner pass with a10
Constraint name col is primary for a15
select a.constraint_type,a.owner,a.table_name,b.column_name,a.r_owner "PrimaryOwner",a."PrimaryConstraintName", r_constraint_name created by a, all_constraints all_cons_columns b where
A.CONSTRAINT_NAME means b.CONSTRAINT_NAME and a.constraint_name 'SYS_C008201';
C = TABLE_NAME OWNER COLUMN_NAME PrimaryOwn PrimaryConstrai- —- ———– —- ————— —— ——— TEST ——p PRIMARY IDENTIFICATION TEST3. Now you can get any of our existing rows of numbers in the reverse child that you want to delete in the main table using IN clause query.
-- I'm only giving you an example, you can also use it to delete data.
select * from TESTFOREIGN where p_id is selected (when id comes from id testprimary where = 2:1;)
option You can disableinclude or data with restrictions and operations performed
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What is integrity constraint in Oracle?
Restrictions A constraint is a declarative means of defining a table rule for a single order. Oracle supports the following set of constraints: a pair of NOT NULL rules bound to null values in another column.
How do you resolve ORA 02292 integrity constraint violated child record found?
To solve this problem, you must first allow them to update or delete a value in some child tables, and then be able to delete the corresponding value in the old table. For example, if you planned the following foreign key (child-parent relationship).
When the below error occurs Ora 02292 integrity constraint violated PK ): child record found?
The error concludes that “constraint fundamentally violates child element – record found.” This certainly indicates that the user was trying to delete a record from the parent table.Name (which is referred to by the international key), but the record exists in the child cabin.
How do I disable referential integrity constraints in Oracle?
Description. After creating a foreign key in Oracle only, you may need to disable the key in the global specific.Syntax. The syntax for disabling a new foreign key in Oracle/PLSQL is: ALTER TABLE table-name CONSTRAINT disable constraint-name;Example.ORA-02292
What are integrity constraints in database?
In database management systems, integrity constraints are predefined sets of rules that are explicitly applied to table fields (columns) or associations to ensure the overall validity, value, and consistency of the data present in a database table.